find dy/dx at point (2,3) on the curve 3x^2+2y^2+xy^2+x-7=0 show full workings

badmus45:
find dy/dx at point (2,3) on the curve 3x^2+2y^2+xy^2+x-7=0 show full workings

F(x,y)=3x² +2y² +xy²+x-7

y'=dy/dx = -Fx/Fy

F_x=6x +y² +1. ( derivative wrt .x)

F_y=4y+2xy ...(derivative wrt . y)

Now dy/dx = -(6x+y² +1)/(4y+2xy)

thus @ (x,y)=(2,3) (I.e dy/dx |(2,3)

=> -[6(2) +(3)² +1 ] /[4(3) +2(2)(3)

=-(12+9+1)/(12+12) =-22/24 =-11/12

that's it .

you are very correct my guy ....thumbs up

lets try these :if y=x/√(a^2 -x^2) show that (a^2-x^2)d2y/dx2=3xdy/dx and pls can i get your mobile num

badmus45:
lets try these :if y=x/√(a^2 -x^2) show that (a^2-x^2)d2y/dx2=3xdy/dx and pls can i get your mobile num

hmm

here

..h.

i was not sure of the answer....sowi

badmus45:
i was not sure of the answer....sowi

post your maths problems here. www.nairaland.com/1147658/nairaland-mathematics-clinic/158#29703680.

2^x =4x find x