(0, 350).each do |x| 
    puts x if((x%7)==0)
end

<?php
for($i=1;$i<=50;$i++)
{
$m=7*$i;
echo "$m<br/>";
}
?>

bakenda:

Complete PHP solution:

<?php
for($i=1;$i<=50;$i++)
{
$m=7*$i;
echo "$m<br/>";
}
?>

Easy does it.

naija_swag:

too trivial!

Fayimora:

I mean he has the code already so no point doing it again

<?PHP
$int = 7;

while($int < 350){
    $int *= 7;
    echo $int . ", ";
}

?> 

<?PHP

for($int = 7; $int < 343; ){ // have difficulties in setting to 350 here
	$int *=7;
	echo $int . ", ";
}

?>

<?php
for($i=1;$i<=50;$i++)
{
echo 7*$i."<br/>";
}
?>

Mobinga:

Wrong. This code can be reduced in terms of everything.

This is the sort of arrogance I dislike.
omo_to_dun which is a programming beast has attempted it. The essence of the challenge is not to get the answer but to see how concise our codes can be. Please attempt it before concluding.
He hasn't simplified it to the last bit!



---
Simplicity.

bakenda:

Here is a little modification of my previous code:

<?php
for($i=1;$i<=50;$i++)
{
echo 7*$i."<br/>";
}
?>

If you have the 'right' solution, it's time to show it-the world is waiting?

<?php
for($i=0;$i<=350;$i+=7)
{
echo $i."<br/>";
}
?>

Mobinga:

Haha see a simplified version of your code

<?php
for($i=0;$i<=350;$i+=7)
{
echo $i."<br/>";
}
?>

I know some of us are used to using i++ as our increment statement. . .then within the for loops blocks we'd now use the modulus operator. That's not clean. As it loops through each one . . . 1, 2 , 3 to  350

You can also pass a numeric value (int oh no go pass 3.434 ) as the increment statement i+=7 << The variable increments in 7's. This optimizes your code and allocates less memory. This can be particularly useful when working on big projects.

Nothing is too trivial. We can all learn.

bakenda:

That code isn't simpler than my code, at best it's same.It's like you didn't notice that my loop terminates at 50 not 350,
though you used an increment of 7 , your loop terminates at 350----about the same number of cycles.

System.out.println("0/n7/n14, " 

naija_swag:

I have been doing a lot of algorithms lately and when I say that this is simple,it isnt arrogance.this is the kind of problems I will solve with my students while teaching.if you know something and you are quite sure of your self,it isnt arrogance and for that i am posting these code,I did in about 10mins after what you wrote got me angry to prove to myself that i wasnt bluffing.[s]its too trivial and i will repeat it again[/s].

public void multiples(){
for(int i=0;i<=350;i++)
if(i%7==0)
System.out.print(i + " ";
}

naija_swag:

I have been doing a lot of algorithms lately and when I say that this is simple,it isnt arrogance.this is the kind of problems I will solve with my students while teaching.if you know something and you are quite sure of your self,it isnt arrogance and for that i am posting these code,I did in about 10mins after what you wrote got me angry to prove to myself that i wasnt bluffing.i[b]ts too trivial and i will repeat it again.[/b]

public void multiples(){
for(int i=0;i<=350;i++)
if(i%7==0)
System.out.print(i + " ";
}

Mobinga:

Nice. I think this is faster though tedious

System.out.println("0/n7/n14, " 

Since it doesn't loop at all. It just prints the string.


We should be doing code-benchmarks more often 

Mobinga:


This is the sort of arrogance I dislike.
omo_to_dun which is a programming beast has attempted it.

Fayimora:

(0, 350).each do |x| 
    puts x if((x%7)==0)
end