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Here I Come Again O.. - Education - Nairaland

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Here I Come Again O.. by Opemiposii(f): 9:44pm On May 04, 2021
if 7th term of an A.P is twice the 3rd term and the sum of 1st four term is 42. find the common diff. the 1st and 10th term
Re: Here I Come Again O.. by clockwisereport: 10:43pm On May 04, 2021
T1 =a= 6

T10= 33

Let me type the solution immediately

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Re: Here I Come Again O.. by clockwisereport: 11:00pm On May 04, 2021
T7 = 2T3.........(1)


T1+T2+T3+T4=42.....(2)

let T1 =a, the first term of the AP

Then, T2=a+d, where d is the common difference;

T3= a+2d;

T4= a+3d;

T7 = a+6d;

substituting (a+6d) and (a+2d) for T7 and T3 in eqn (1)

a+ 6d = 2(a+2d)

a+ 6d = 2a+4d

collecting like terms

a-2a = 4d- 6d

-a = -2d

a = 2d..........(3)

From eqn (2)

T1+T2+T3+T4 = 42

a+(a+d)+ (a+2d)+(a+3d) = 42

4a+6d = 42.......(4)

from eqn (2), a = 2d

4(2d) + 6d = 42

8d + 6d = 42

14d = 42

d= 42/ 14 = 3

d = 3

Recall that from eqn (3) , a = 2d

=> a = 2(3) = 6


T10 = a + 9d

= 6+ 9(3)
=6+27
=33

@opemisiposii

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Re: Here I Come Again O.. by Opemiposii(f): 6:22am On May 05, 2021
clockwisereport:
T7 = 2T3.........(1)

T1+T2+T3+T4=42.....(2)
let T1 =a, the first term of the AP
Then, T2=a+d, where d is the common difference;
T3= a+2d;
T4= a+3d;
T7 = a+6d;
substituting (a+6d) and (a+2d) for T7 and T3 in eqn (1)
a+ 6d = 2(a+2d)
a+ 6d = 2a+4d
collecting like terms
a-2a = 4d- 6d
-a = -2d
a = 2d..........(3)
From eqn (2)
T1+T2+T3+T4 = 42
a+(a+d)+ (a+2d)+(a+3d) = 42
4a+6d = 42.......(4)
from eqn (2), a = 2d
4(2d) + 6d = 42
8d + 6d = 42
14d = 42
d= 42/ 14 = 3
d = 3
Recall that from eqn (3) , a = 2d
=> a = 2(3) = 6

T10 = a + 9d
= 6+ 9(3) =6+27 =33
@opemisiposii
God will bless u for me. amen

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Re: Here I Come Again O.. by cayorday89(m): 3:09pm On Jul 24, 2021
clockwisereport:
T7 = 2T3.........(1)


T1+T2+T3+T4=42.....(2)

let T1 =a, the first term of the AP

Then, T2=a+d, where d is the common difference;

T3= a+2d;

T4= a+3d;

T7 = a+6d;

substituting (a+6d) and (a+2d) for T7 and T3 in eqn (1)

a+ 6d = 2(a+2d)

a+ 6d = 2a+4d

collecting like terms

a-2a = 4d- 6d

-a = -2d

a = 2d..........(3)

From eqn (2)

T1+T2+T3+T4 = 42

a+(a+d)+ (a+2d)+(a+3d) = 42

4a+6d = 42.......(4)

from eqn (2), a = 2d

4(2d) + 6d = 42

8d + 6d = 42

14d = 42

d= 42/ 14 = 3

d = 3

Recall that from eqn (3) , a = 2d

=> a = 2(3) = 6


T10 = a + 9d

= 6+ 9(3)
=6+27
=33

@opemisiposii
Full respect from this side cos if no be 1+1 maths I no dey do, even if money calculation gets complex, Man pikin go just find the easy way out ni ooo...

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